Formula for calculating Motor Capacity

Rotary motion Linear motion (Horizontal motion) • Po = 2p • Tl • N  60 • p x 10-3 [kW] • Po = m • W • Vl 6120 • h [kW] • Pa = 4Jl • (Nl)2 365 X 103 • ta   [kW] • Pa = W • (Vl)2 3600 X 103 • ta [kW] • TL = Nl NM• h • Tl [N• M] • TL = 9.8 m • W • Vl 2p • NM • p [N• M] • JL= Nl Nm •Jl [kg • m2] • JL = 1  Vl 4    p • NM [kg • m2] • ta = 2p (JM + JL) • NM 60 • (TM • a - TL)   [sec] • ta = 2p (JM + JL ) •NM 60 • (TM • a - TL) [sec] • td = 2p (JM + JL) • NM 60 • (TM • b + TL)   [sec] • td = 2p (JM + JL) • NM 60 • (TM • b + TL) [sec]

Legend       Po : Running power [kW] Tl : Load torque [N • m] Pa : Required power for accel [kW] TL : Load torque [N • m] Nl : Load speed [r/m]     (Reflected to motor shaft) NM : Motor shaft speed [r/m] TM : Motor rated torque[N.m] Vl : Load velocity of load [m/min.] ta : Acceleration time [sec] h : Machine efficiency td : Decceleration tiem [sec] m : Friction factor a : 0.8 - 1.2 W : Weight of load [kg] b : 0.1 - 0.2 (200V class) 0.05 - 0.1 (400 V class) JM : Motor inertia [kg • m2]       Jl : Load inertia [kg • m2]       JL : Load inertia [kg • m2] (Reflected to motor shaft)